07-11-2007, 19:03 | #1 |
Screaming Orgasm
Join Date: Jul 2006
Location: Newbury
Posts: 15,194
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One for the camera and/or maths buffs
An object approximately 75 feet long by 50 feet wide is visible 81,000 feet away and occupies approximately 1/16th of the total frame on a TV camera (16:9 aspect ratio).
Approximately what zoom lens would this require? PS - I realise this information is incomplete - your best guess will be fine as this is only to satisfy my curiosity. |
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